Python 数据结构 - 集合和冻结集（2024）
上次更新时间：2024-12-16
课程售价: 2.9 元
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课程内容
01 - Introduction
02 - 1. Introduction to Sets
03 - 2. Set Operations
04 - 3. Operators and Methods
- 01 - Understand set theory with an example
- 02 - Find all the elements present in different sets
- 03 - Find the common elements present between the sets
- 04 - Determine the difference between two sets
- 05 - Determine the symmetric difference between two sets
- 06 - Determine whether two sets have any common elements
- 07 - Determine whether one set is a subset of another
- 08 - Determine whether one set is a superset of another
- 09 - Solution List unregistered students
05 - 4. Modifying a Set
- 01 - Add an element to a set
- 02 - Add multiple elements with the update() method
- 03 - Remove an element from a set
- 04 - Remove an element from a set using discard()
- 05 - Using pop() to remove and return an element from a set
- 06 - Clearing all elements from a set
- 07 - Solution Filter by the first character
06 - 5. Using Built-In Functions
07 - 6. Frozen Sets
08 - 7. Sets and Frozen Sets Internals
09 - 8. Pros and Cons
10 - 9. Application Ideas
11 - Conclusion
课程内容
11个章节 , 44个讲座
01 - Introduction
02 - 1. Introduction to Sets
03 - 2. Set Operations
04 - 3. Operators and Methods
- 01 - Understand set theory with an example
- 02 - Find all the elements present in different sets
- 03 - Find the common elements present between the sets
- 04 - Determine the difference between two sets
- 05 - Determine the symmetric difference between two sets
- 06 - Determine whether two sets have any common elements
- 07 - Determine whether one set is a subset of another
- 08 - Determine whether one set is a superset of another
- 09 - Solution List unregistered students
05 - 4. Modifying a Set
- 01 - Add an element to a set
- 02 - Add multiple elements with the update() method
- 03 - Remove an element from a set
- 04 - Remove an element from a set using discard()
- 05 - Using pop() to remove and return an element from a set
- 06 - Clearing all elements from a set
- 07 - Solution Filter by the first character